is_member_of

[gbrain]

Hi, within the VB structure you can use the following.

<if condition="is_member_of($bbuserinfo, 5, 6)">
button code
</if>

But is there a way to call the is_member_of from within a PHP page as a function

<?
if ($is_member_of($vbulletin->userinfo['membergroupids'], 1)
{
 echo "test";
}
?>

thanks

Gary

[SNN]

(Just a note, the more appropriate place is either the HTML/PHP questions, or vBulletin.org)

Yes, you can use is_member_of() from a PHP page, but it's:

<?php
if(is_member_of($vbulletin->userinfo, 5, 6) {
  print "You are in usergroup five or six!";
}
?>

[gbrain]

Hi, noted.

But for me that does not work.

<? if (is_member_of($vbulletin->userinfo, 20)) { ?>

I currently use so I know I can read the VB variables.

<? if ($vbulletin->userinfo['membergroupids'] == 20) { ?>

will do so more digging.


Thanks anyway.

G.


[update] dont know why but it started to work very strange. thanks again.

[SNN]

I would guess the problem started when you had a '$' before the function name :P no problems.

[Wayne Luke]

Your second if conditional would fail if a user had more than one secondary usergroup and doesn't check to see if their primary usergroup is 20. If a user is in multiple secondary usergroups, membergroupids becomes a comma delimited string.

I know you got is_member_of working, but I wanted to point that at.

[gbrain]

Your second if conditional would fail if a user had more than one secondary usergroup and doesn't check to see if their primary usergroup is 20. If a user is in multiple secondary usergroups, membergroupids becomes a comma delimited string.

I know you got is_member_of working, but I wanted to point that at.

Hi thanks for the comments and yes it would which is why I was looking to get the is_member working.

And yes SNN It was the $ and I was using userinfo['membergroupids']

Cheers again

G.